2x^2+9x+26=-4x+5

Solution for 2x^2+9x+26=-4x+5 equation:

2x^2+9x+26=-4x+5

We move all terms to the left:

2x^2+9x+26-(-4x+5)=0

We get rid of parentheses

2x^2+9x+4x-5+26=0

We add all the numbers together, and all the variables

2x^2+13x+21=0

a = 2; b = 13; c = +21;
Δ = b2-4ac
Δ = 132-4·2·21
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-1}{2*2}=\frac{-14}{4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+1}{2*2}=\frac{-12}{4}
=-3
$